Calculating number of pages from number of entries

[jollekox]

I have 47 entries of text in an SQL database, in Perl, I want to print out the last 15 of these (this is simple, I manage to do this), but I also want to print out how many pages these 47 entries would "occupy", if each page displays 15 entries.

I could do something like this:

$entries = 47;

$pages = int($entries / 15);
$page = $entries / 15;

This renders unusable due to inaccuracy concerning floats to integers.
(And if the number og entries is smaller than 15, I will get a 0 from int(),
this can easely be fixed like this:

if ($pages == 0) {$pages = 1;}

But a number like 47 will return 3.13 when divided by 15, so I will have to increment it to 4 instead of 3.

How should I solve this problem? Thanks in advance!

 

[PaulTEG]

$pages=$entries/$lines_per_page;
if ($pages > int($pages)) { $pages++; }

Is this what you're looking for
HTH
--Paul

 

[jollekox]

I didn't quite get that one to work, but at this point, I am using this one:

$pages = $entries / 15;

unless ($pages !~ /./) {
$pages = int($pages);
$pages ++;
}

Thanks for your help!

 

[duncdude]

$entries = 47;

@entriesPerPage = (15, 16, 23, 24, 1, 46, 47, 48);

foreach $entriesPerPage (@entriesPerPage) {
$pages = ($entries-1) / $entriesPerPage;
print "$entries entries @ $entriesPerPage entries/page would make ".int(++$pages)." page(s)\n";
}


Kind Regards
Duncan

 

[webpager]

I hope this helps
I have a prog which requires knowing the size of a file in order to fit on a 1.44M floppy. Surely you remember those - ha ha.
I write the information to a text file then get the size of the text file. The purists will say I am taking up valuable server time but it gets the job done and causes no problems to our system. Maybe an adaptation of this idea could solve your problem.
Keith

 

[stevexff]

jollekox

The following seems to work OK, even when there are zero entries returned from the SQL call:

$entries = 47;
$page_size = 15;

$pages = int(($entries + $page_size - 1)/$page_size);

unless you want to argue that it takes 1 page to tell the user that there are no entries...

Steve