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bash string check 1

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w5000

Technical User
Nov 24, 2010
223
0
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PL

Hello,
why test returns "clean" what is marked in red in belongs strings comparison?

Code:
# d=274y82heE
# [[ $d =~ [^[:alnum:]] ]] && echo "not clean $d" || echo "clean $d"
[COLOR=#4E9A06]clean 274y82heE[/color]
# d=274y82he^E
# [[ $d =~ [^[:alnum:]] ]] && echo "not clean $d" || echo "clean $d"
[COLOR=#4E9A06]not clean 274y82he^E[/color]

# d=/one/ssfdsf/274y82he^E/end/end
# [[ $d =~ /one/ssfdsf/[^[:alnum:]]/end/end ]] && echo "not clean $d" || echo "clean $d"
[COLOR=#EF2929]clean /one/ssfdsf/274y82he^E/end/end[/color]
# [[ $d =~ /one/ssfdsf/[[:alnum:]]/end/end ]] && echo "not clean $d" || echo "clean $d"
[COLOR=#EF2929]clean /one/ssfdsf/274y82he^E/end/end[/color]
# [[ $d =~ ^/one/ssfdsf/[[:alnum:]]/end/end ]] && echo "not clean $d" || echo "clean $d"
[COLOR=#EF2929]clean /one/ssfdsf/274y82he^E/end/end[/color]
# [[ $d =~ ^/one/ssfdsf/[[:alnum:]]/end/end$ ]] && echo "not clean $d" || echo "clean $d"
[COLOR=#EF2929]clean /one/ssfdsf/274y82he^E/end/end[/color]
 
Hi

[ul]
[li][tt][[:alnum:]][/tt] - one alphanumeric character[/li]
[li][tt][^[:alnum:]][/tt] - one non-alphanumeric character[/li]
[/ul]
In that place you have 8 alphanumeric character, then 1 non-alphanumeric character, then 1 alphanumeric character.

Not sure what is your goal, but try something like this :
Bash:
[[ $d =~ /one/ssfdsf/.*[^[:alnum:]].*/end/end ]]

Feherke.
feherke.ga
 
hello,

ok. but it doesn't return clean when I expect it clean:

Code:
# d=/one/ssfdsf/274y82heE/end/end
# [[ $d =~ ^/one/ssfdsf/[[:alnum:]].*/end/end$ ]] && echo "not clean $d" || echo "clean $d"
not clean /one/ssfdsf/274y82heE/end/end

the goal is to check if there is "alnum" between ^/one/ssfdsf/ and /end/end$
 
Hi

Your current regular expression says :
[ul]
[li]starts with "/one/ssfdsf/"[/li]
[li]then 1 alphanumeric character[/li]
[li]then any number of any character[/li]
[li]ends with "/end/end"[/li]
[/ul]
As your current string looks exactly like that, so the 1[sup]st[/sup] [tt]echo[/tt] gets executed, saying "not clean".

w5000 said:
the goal is to check if there is "alnum" between ^/one/ssfdsf/ and /end/end$
Your current regular expression says in that place has to be 1 alnum followed by anything or nothing.

I think you want this, so in that place to have 1 or more alphanumeric characters :
Bash:
[[ $d =~ ^/one/ssfdsf/[[:alnum:]]+/end/end$ ]] && echo "clean $d" || echo "not clean $d"


Feherke.
feherke.ga
 
thx.
indeed, I was pretty sure I had tested [[:alnum:]]+ in one of my first tries... I must had done some mistake
 
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