Awk command 1

[nwo4life]

I have a script that looks like this I need it to drop the
directory and the gz of the filename. All I want is (test.test2.tar) for f. With this it gives me test.test2.tar.gz. Any help appreciated. Thanks

Example filename
/tmp/backup/test.test2.tar.gz

for i in `ls $dir/*.tar.gz`
do
echo $i
f=`exho $i | awk -F/ '{print $3}'`
gunzip $i
tar xvf $f.tar
gzip $f.tar
Done

 

[CaKiwi]

Try

f=`echo $i | awk -F/ '{sub(/\.gz$/,"",$3);print $3}'`

CaKiwi

 

[aigles]

basename dors all work

for i in `ls $dir/*.tar.gz`
do
echo $i
f=`basename $i .gz`
gunzip $i
tar xvf $f.tar
gzip $f.tar
done

Jean Pierre.

 

[nwo4life]

Thanks Aigles it worked