assignment and passing shell variable

[daula]

hi everyone;
i want to take a shell variable and pass it to the -f (external file) option of awk.

i have tried a couple of ways and neither works.
btw, the reason i'm trying to achieve this is because for every input file there is an associated awk file (e.g IDA1.xml is associated to IDA1.sub etc).

any help is appreciate.

thanks in advance.

daula

TALLY="$1"
OUT_FILE="$4"
FORM="$2"
AXIS="$3"
.
.
.

function func ()
{
  echo `expr substr $TALLY 4 1`
}

my_id=`eval func`
sub="IDA$my_id.sub"

1) 
awk -v FORMAT="$FORM" -v xAXIS="$AXIS" -f '"$sub"' "$TALLY" > "$OUT_FILE"

2) 
awk -v FORMAT="$FORM" -v xAXIS="$AXIS" -f "'"$sub"'" "$TALLY" > "$OUT_FILE"

 

[PHV]

And what about simply this ?
-f $sub

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[daula]

phew! that works.
thanks PHV

 

[daula]

hello again;
i have another variable related question...
in the "sub" file (mentioned in my previous post), i have an search/action like:

/:name="cState">/{++r;next}

now, i'm wondering is there a way i can pass "cState" or even the whole search string ":name="cState"" as a variable?

many thanks

daula

 

[PHV]

Replace this:
/:name="cState">/{++r;next}
with this:
$0~":name=\""vName"\"">/{++r;next}

And then:
awk -v FORMAT=$FORM -v xAXIS=$AXIS -v vName=cState -f $sub $TALLY > $OUT_FILE

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[daula]

Thank PHV
although awk complained "unterminated regexp" and "unexpected newline".
i mananged to fix it tho...

$0~":name=\""vName"\">"/{++r;next}

thanks again for lead/tip

daula

 

[PHV]

OOps, sorry for the typo:
$0~":name=\""vName"\">"{++r;next}

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886