arrays of pointers again

bigE · Jun 27, 2000

Sorry I did'nt put all the information necessay in the first email. Below is the basics of what I am trying to do. I am just trying to form an array of pointers to six two-dimensional integer arrays. Afterwards I want to retrieve them and print them out. Since my last email I have tried a few other things but I am still having problems. Here's the code. #include <stdio.h> #include <stdlib.h> #include <string.h> void displacement_from_source(int X, int u_position[4][2],int* rx_displacement[6]); void print_out_arrays(int X, int* rx_displacement[6]); // Main Program void main () { /* global variables */ int i,j; int u_position[4][2]={5,6,7,8,9,10,11,12}; int X; int* rx_displacement[6]; //array of pointers int*tx; int temp_array[4][2]; for (X=0; X<6; X++) // go through six times to form the six integer arrays { displacement_from_source(X,u_position,rx_displacement); } for (X=0; X<6; X++) //go through six times to print arrays { tx=rx_displacement[X]; //assign pointer tx the first interarray address memcpy(temp_array,tx, 8*sizeof(int)); //assign this address to temp_array  for (i=0;i<4;i++)  { for (j=0;j<2;j++) { printf("%d\n", temp_array[j]); }  } } } void displacement_from_source(int X, int u_position[4][2],int* rx_displacement[6]) { int i,j; int rx_array[4][2]; int rx_temp[4][2]; int* rx; int* tx;   memcpy(rx,rx_temp, 8*sizeof(int)); //assign the address of rx_temp to the pointer rx rx_displacement[X]=rx; //assign the address of rx to the array of pointer's Xth for (i=0;i<4;i++) { for (j=0;j<2;j++) { rx_temp[j]=u_position[j]; } } }

zBuilder · Jun 27, 2000

Here is some simple code that I threw together that shows how to use pointers with 2 dimensional arrays: #include <stdio.h> int main() { char (*x)[15]; char y[10][15]; int z; for (z=0; z<10; z++)    {    sprintf( &(y[z][0]), "hello %d\n", z);  // Fill the array Y with data    }    x = y;  // Assign the pointer X to point to the array Y for (z=0; z<10; z++)    {    printf( "%s", &x[z][0] );  // Print out the array Y using pointer X    } return 0; } <a href=mailto:Kim_Christensen@telus.net>Kim_Christensen@telus.net</a> <a href=

http://www3.bc.sympatico.ca/Kim_Christensen/index.html>Home

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bbhaskar · Jun 27, 2000

Hi ,    heer I am posting you the code with lots of modificatoins. This will surle help you . If at-all you have any problem then fell free to call me ... #include <stdio.h> #include <stdlib.h> #include <string.h> void displacement_from_source(int X, int u_position[4][2],int* rx_displacement[6]); void print_out_arrays(int X, int* rx_displacement[6]); // Main Program void main () { /* these are not global variables */ int i,j; int u_position[4][2]={5,6,7,8,9,10,11,12}; int X; int* rx_displacement[6]; //array of pointers int*tx; int temp_array[4][2]; for (X=0; X<6; X++) // go through six times to form the six integer arrays { displacement_from_source(X,u_position,rx_displacement); } for (X=0; X<6; X++) //go through six times to print arrays { tx=rx_displacement[X]; //assign pointer tx the first interarray address memcpy(temp_array,tx, 8*sizeof(int)); //assign this address to temp_array  for (i=0;i<4;i++)  { for (j=0;j<2;j++) { printf("%d\n", temp_array[j]); }  } } } void displacement_from_source(int X, int u_position[4][2],int* rx_displacement[6]) { int i,j; int rx_array[4][2]; int rx_temp[4][2]; int* rx; int* tx;   memcpy(rx,rx_temp, 8*sizeof(int)); //assign the address of rx_temp to the pointer rx rx_displacement[X]=rx; //assign the address of rx to the array of pointer's Xth for (i=0;i<4;i++) { for (j=0;j<2;j++) { rx_temp[j]=u_position[j]; } } } Bhaskar Bora <a href=mailto:bhaskar_bora@yahoo.com>bhaskar_bora@yahoo.com</a> <a href= > </a> ___________________________________________________________ 
C and C++ are too Cool ... Like CoSSAP .. 
Ooops What's this CoSSAP...?? 
It's a Objected oriented language created by me ...

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arrays of pointers again

bigE

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zBuilder

MIS

bbhaskar

Programmer

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