array and variable in Korn Shell 2

[SysAdminUnix]

Hi,

I'm trying to create a script with a variable array. First I'll set the array's. After that I'm going into a loop so I can call all three array's in one pass.

set -A system1 250 1.2.3.4 routerUS01.nl.com
set -A system2 250 2.3.4.5 router2501.nl.com

echo ${system1[0]}"; "${system1[1]}"; "${system1[2]}"."
typeset -i arraywaarde=1
while [ ${arraywaarde} -lt 3 ]
do
vrarray0=\$\{system${arraywaarde}"[0]"\}; echo ${vrarray0}
vrarray1=\$\{system${arraywaarde}"[1]"\}; echo ${vrarray1}
vrarray2=\$\{system${arraywaarde}"[2]"\}; echo ${vrarray2}
arraywaarde=${arraywaarde}+1
done

When I execute the script, I get the following results:
250; 1.2.3.4; routerUS01.nl.com.
${system1[0]}
${system1[1]}
${system1[2]}
${system2[0]}
${system2[1]}
${system2[2]}

I expected to get:

250; 1.2.3.4; routerUS01.nl.com.
250
1.2.3.4
routerUS01.nl.com
250
2.3.4.5
router2501.nl.com

Why am I getting the name of the variable instead of the value? How can this be solved. I tried lots but nothing seems to work anymore.

 

[dickiebird]

You've escaped the $ and the { , rendering them as the actual $ sign and { sign
Why ?

Dickie Bird (-)))

 

[Ygor]

Try using eval...

vrarray0=\$\{system${arraywaarde}"[0]"\}; eval echo ${vrarray0}
vrarray1=\$\{system${arraywaarde}"[1]"\}; eval echo ${vrarray1}
vrarray2=\$\{system${arraywaarde}"[2]"\}; eval echo ${vrarray2}

 

[SysAdminUnix]

To dickiebird:
If I remove the escape characters then the following error occurred:
250; 1.2.3.4; routerUS01.nl.com.
./lol[8]: vrarray0=${system${arraywaarde}"[0]"}: The specified substitution is not valid for this command.

To Ygor:
eval did the solution. Works now:

250; 1.2.3.4; routerUS01.nl.com.
250
1.2.3.4
routerUS01.nl.com
250
2.3.4.5
router2501.nl.com

Thx both for the assistence.

 

[Annihilannic]

vrarray1=\$\{system${arraywaarde}"[1]"\}; has to be evaluated by the shell twice, the first time to replace "system${arraywaarde}" with system0, for example, and the second time to get the contents of the array.

In my solution I put the eval in a different place, but Ygor's works equally well.

Also arraywaarde=${arraywaarde}+1 would only set the value of arraywaarde to "0+1" instead of "1". You need to surround it in $(( ... )) to actually calculate the new value, or alternatively use ((arraywaarde=arraywaarde+1)).


[tt]#!/bin/ksh
set -A system1 250 1.2.3.4 routerUS01.nl.com
set -A system2 250 2.3.4.5 router2501.nl.com

echo ${system1[0]}"; "${system1[1]}"; "${system1[2]}"."
typeset -i arraywaarde=1
while [ ${arraywaarde} -lt 3 ]
do
eval vrarray0=\$\{system${arraywaarde}"[0]"\}; echo ${vrarray0}
eval vrarray1=\$\{system${arraywaarde}"[1]"\}; echo ${vrarray1}
eval vrarray2=\$\{system${arraywaarde}"[2]"\}; echo ${vrarray2}
arraywaarde=$((${arraywaarde}+1))
done[/tt]

Annihilannic.

 

[SysAdminUnix]

Thx Annihilannic for the solution. Works also, and seems a better (read neater) solution. Off course the vars vrarray* will be used through the entire script, so your solution will be best, since the eval should run only once.