Add two hexadeximal number

[csudess]

How could i add two hexadecimal number? thank u for ur answer

 

[csudess]

so then!
i would like to do this

$numb1="\x64";
$numb2="\x01";

$value=$numb1+$numb2;
print "$value"; #
it would be really good if the $value would eg \x65!

but its not!

 

[Annihilannic]

\x64 means the character represented by 64 hexadecimal in the current character set (usually a lower case 'd'). You can use the syntax 0x64 for hexadecimal constants in perl.

Do add and print hexadecimal numbers you need to use something like:

$numb1=0x64;
$numb2=0x01;
$value=$numb1+$numb2;
printf "0x%x\n",$value;

The %x means to insert the value of $value into the format string in hexadecimal format. See perldoc -f printf and especially perldoc -f sprintf for details about output formats.

Annihilannic.