Accessing USB-device: How to determine lpFileName in CreateFile call

[arnoldw]

I am trying to communicate (send and receive ASCII-characters) with a USB-barcode printer. In order to get a handle to the device I believe I have to call CreateFile and it has the following prototype:

HANDLE WINAPI CreateFile(
__in LPCTSTR lpFileName,
__in DWORD dwDesiredAccess,
__in DWORD dwShareMode,
__in_opt LPSECURITY_ATTRIBUTES lpSecurityAttributes,
__in DWORD dwCreationDisposition,
__in DWORD dwFlagsAndAttributes,
__in_opt HANDLE hTemplateFile
);

How do I determine what the first parameter should be? I guess it should be something similar to

"\\\\.\\xxxUSBxxx"

Where can I look for clues on what this string should be?

 

[whosrdaddy]

look here for more info:

http://www.microsoft.com/communitie...vers&tid=034fb189-16b3-4736-99e8-40bf041eb40c

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[arnoldw]

Many thanks for this most valuable link!