Accessing specific characters in a scalar 1

[twitaboy]

Hey Tek-Tips,
I have a database full of dates in the form of year/month/day/time/second in a string of characters.

Eg. 20030102030405 is 2003, January the second, at 3.04.05 am.

I am attempting to parse the dates in the format they are in, back into separate variables.

Eg.
$year = "2003";
$month = "01";
$day = "02";

I figured I could do something like this:
$year = $rawdate[01];

but that doesn't work.

Any ideas, tips, or code, would be very greatly appreciated.

Thanks,
twitaboy

 

[raklet]

Do something like this:

$date = " 20030102030405"

my ($year,$month,$day) = $date =~ /(....)(..)(..)/;

 

[twitaboy]

Thanks heaps raklet, 100% correct and helpful.