2 simultaneous exceptions? 3

[cpjust]

Hi,
I just thought of something kind of scary, so I was wondering if anyone knows the answer.
I know in C++, if you're in a destructor because an exception was thrown and then you throw another exception, the program immediately calls the std::terminate() function and ends.

I'm wondering if the same kind of thing would happen in Java if you throw an exception from a try block and then throw another exception in a finally block? You would essentially have 2 exceptions in the air at the same time...

 

[snitin78]

Nope. You will only have the exception from the finally block.

 

[cpjust]

So the first exception just disappears?
So in this code:

try
{
   throw new SomeException();
}
catch ( SomeException e )
{
   throw new SomeOtherException( e );
}
finally
{
   throw new YetAnotherException();
}

Only YetAnotherException will come shooting out of the function?

 

[tom62]

Yes, YetAnotherAcception comes shooting out ot the function.
SomeException is caught by the catch and SomeOtherException by the finally

 

[cpjust]

Wow, that's strange... finally catches exceptions if it throws them, but not in other cases.
But at least Eclipse gave me a warning that I was about to do something stupid in my finally block when I tried it out.

 

[timw]

I wouldn't say that 'finally' actually catches exceptions. Rather, all paths lead through the finally and if you throw any exceptions from within 'finally' they silently replace any other which is pending.

Tim

 

[Diancecht]

It's funny. If you wrap that in a method, you will need to add a throws clause only for the YetAnotherException ...

Cheers,
Dian

 

[timw]

The Java compilers and JVM are indeed very clever

Tim