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thanks for the reply. i installed apache 1.3.22 and all is fine... would like to use apache 2.0.x though but oh well. ######## CtN ########

Hi I have Windows 2000 sp4 running apache2.0.48 and PHP4.3.2(cgi). I've been using this configration for a while and installed apache and php on win2k many many times without any problems. Now, I did a clean install of Windows 2000 and I cant get my php to work. Running any php script gives me...

Symptoms I had relating directly to the blaster worm: * svchost.exe error directly after connecting to the network * rpc error when installing new software * cannot copy and paste anything * cannot ctrl-n to open new window in ie * cannot ctrl-f to find in ie All fixed except for some issues...

Hi I had same problem and after searching the net i found that all symptoms pointed to the blaster worm virus. I downloaded all fixes including the rpc exploit fix for win2k. All virus fixes reported that the virus was not found on my system, so I continued anyway and ran the rpc update and...

no error msg. i cannot use the LOOK IN drop down tp browse the workgroup to add people in the permission list. ######## CtN ########

what baffles me is the fact that my friend can click on the LOOK IN drop-down box to select a workgroup to look in. mine is greyed out on my own computer name. ######## CtN ########

hello. my friend and i are both using win2k pro on a local area network. when sharing a directory for him to access across the network i cannot LOOK IN Workgroup to add permissions. i can only see my own computer in the LOOK IN field. we can both see each other in my network places, but cannot...

hi, I know it's not really necessary to define all variables but i'd like to do so anyway. when i use var $myvar; i get a parse error. how else can i define a variable? thanx ######## CtN ########

Hi, How exactly does this pseudo-service work? Can I ran an app on win9x as a service? thanx ######## CtN ########

Hi, What is the difference between $HTTP_SERVER_VARS["REMOTE_ADDR"] and $HTTP_SERVER_VARS["REMOTE_HOST"] On IIS I get a value for $HTTP_SERVER_VARS["REMOTE_HOST"] but not on Apache? On Apache only $HTTP_SERVER_VARS["REMOTE_ADDR"] works. thanx ########...

hi, how can i copy all the files(files only) in a bunch of sub-directories to a new directory. i want to copy files only, not directories. thanx chris ######## CtN ########

don't worry, it works fine now. the reason i got the exception was because i checked the primary key for duplicates which cannot duplicate anyway. thanx it works fine ######## CtN ########

ok, i understand now what values are being returned from the sql query, but how do i output any of those values? my query: SELECT COUNT(*),Category FROM product GROUP BY Category HAVING COUNT(*) > 1 the output i got was two columns: XPR1000 and Category with values 6 bla1 6 bla2 how can i...

thanx alot. i get the idea. i'll go give it a go. ######## CtN ########

i'm using asp. i basically want sql to go to the first row it finds where the value of name is 'Joe' and update that row with the new values and then stop. ######## CtN ########

hi, i don't quite understand howto use cmmrfrds's example above. could you explain it to me please? thanx chris ######## CtN ########

hi, will it not work if i only use: UPDATE ONCE mytable SET country='ZA' WHERE name='Joe' ?? thanx Chris ######## CtN ########

Hi, i get asp error: Error Type: (0x80020009) Exception occurred. my code: sqlVerQ = "SELECT COUNT(*), Productid FROM product GROUP BY Productid HAVING COUNT(*) > 1" set rsVer = objConnPr.execute(sqlVerQ) response.write "Number of Duplicate Records: " & rsVer(0) &...

Hi, Say i've got in a table two records both with a name value of Joe. I want to update ONE of these records(doesn't matter which). Is it possible to have something like: UPDATE ONCE mytable SET country='ZA' WHERE name='Joe' thanx Chris ######## CtN ########

Hi, Say i've got in a table two records both with a name value of Joe. I want to update ONE of these records(doesn't matter which). Is it possible to have something like: UPDATE ONCE mytable SET country='ZA' WHERE name='Joe' thanx Chris ######## CtN ########