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Thanks...

I want my Java Variable to be set by my PHP variable I have a Variable called Siteip Its a java variable I have a Variable called $ip that is PHP how do I set the Siteip variable to equal the $IP in PHP ? Thanks

1st question revised: If I want the variable java variable ip to be set to what the php variable $siteip is there a format to do that in PHP? ----------------------------------- 2nd question revised: Any simple example on how to set a cookie in PHP Lets say I want the cookie called "Name"...

Two questions from this Beginner If I want to transfer a variable thats PHP to one thats JAVA how do I do that? 1st question: If I have one like var IP = and I have an $IP in PHP but I want IP to be the $IP for JAVA ? ----------------------------------- 2nd question: Any simple example on...

Thanks Guys...

How do I create a temporary flag variable say $flag that can be checked from one page to another using an if ($flag=="1"){ statement. I dont want to save it in the database but I still want to flag it and unflag it from time to time... Thanks Chuck

Thanks Guys... Awesome...

If I have a statement like if (!$result1){ $logonsuccess = 0; How would I include a $result2 check so that if either result tested ok the if statement would work? Thanks Chuck

Thanks... Cool

I have a form (like who doesnt) And way Id like to place some of my PHP variables like $user etc... into the form as it is modifying a selected user... How can I make the value= in an html form be equal to the variable ? Thanks Chuck

Thanks ...

How do I take say $user and $room where $user = "chuck" and $room = "lobby" and make it so that $userroom = "chuck lobby" Thanks Chuck

Thanks For the help, I see it now...

I have programmed a lot in Java Script there is a location = command you can use to re-direct the page to another page... Is there a way in PHP to excute a line of code that loads another whole page replacing the existing one? Thanks A million

Thanks all I had to do is sub the id for userID like in the database and that works fine... Cool....

When I do try mysql_fetch_array($result) I get array

I have a table with the following user passwd email userlevel nick room ip $ID is = the current logged in users ID which is 24 when I test. Yet when I run this from the web page $sql = "SELECT * FROM phpSP_users"; $result=mysql_query($sql) or die("Blah"); I get Resource id #7 as my...

I have a table with the following user passwd email userlevel nick room ip $ID is = the current logged in users ID which is 24 when I test. Yet when I run this from the web page $sql = "SELECT * FROM phpSP_users"; $result=mysql_query($sql) or die("Blah"); I get Resource id #7 as my...

I am completely new to SQL I connect to the database ok and the table is phpSP_users when I run this statement or others changed a bit I either get the "Blah" or id = 24 Resource id #7 Thank you! I am looking to get the info on userID 24 which is am sure $ID equals... The odd part is on...