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The result is show'n in hex. succes, Tessa

Then trow it out of the window. Look for the police first athorwise you get a fine. Tessa p.s. You can allmost allways run a linker on a os.

And I in some others. Tessa

p.s I read a bit back in the post and sow that you are using a 32 bit linker. Thats the main error in your handling the code. Just use Link or any other 16 bit real mode linker and your error will not pop up again. In 32 bit mode (called the protected mode) segment registers are not handled any...

[CODE] MODEL small .STACK 64 .DATA DATA1 DB 52H DATA2 DB 59H SUM DB ? .CODE MAIN PROC FAR MOV AL, DATA1 MOV BL, DATA2 ADD AL, BL MOV SUM, AL MOV AH, 4CH INT 21H MAIN ENDP...

If you use the model small, what is the same as tiny, you can't use segment definitions. So the code MOV AX,@DATA is wrong, as it assumes that you are using a one segment program. All the segment registers are set to the same page. Succes, Tessa

Try just saying .MODEL LARGE then windows will accept it as being a 16 bit common DOS kind of program. If you run it, windows see's its a REAL mode program and will use the DOS INT code's. You will just get the message: program terminated normaly, since you do nothing more than start en en the...

Dear all, The stack is growing down, not up. So if you move sp to bp then push the number the only way to get your data is to subtract. mov bp,sp push 54h ..... mov ax,[bp-2] or mov cx,[bp-2] afther doing the near call mov ax,[bp-2] or mov cx,[bp-2]...

I saw one on e-bay a couple of weeks ago. Sombody paid about 120,00 dollars for it. Ok, it was the special gold version.

The question remains: - are you building a motherboard - are you building a processor the be placed on a motherboard - if you are not building your own processor, what kind of processor are you going to use. Keep in mind that a high frequenty processor ask's for a very different design...

All of the above are correct. Indirect addressing, as it says, lets you get the memory value that is pointed by the given register. So if EAX = 100 mov ebx,[eax] gets the 100th dword relativ to DS into EBX. mov [eax],ebx puts the contents of EBX into the double word at address...

Your code has no controled end and therefore your program will continue into some old code and crashes. So you must end it with some code, see your book. Tessa

The only thing I'm allways curious about is, like lionelhill is asking: what grade did we get. And denc is just stating what I think about answering this kind of questions, its fun to find out a simple and compleet answer. Tessa

Like any library you can replace the existing object code in it with your own. But be carefull that your code is errorless. Assemble the source --> build an object file and link it into the existing library. If you don't know how check the manual that come's with your compiler/assembler...

Since a DLL is just a Library, you could extract the object you wanted to change, write your one, and insert that in the DLL. For all those people that ask this question in this forum I will once tell what DLL stands for. DLL == Dynamic Link Library, It can be build by almost anly linker that...

You can put the wait allmost anywere, but be sure that you let the global interrupt enabled. That is: use a CLI before you goto the WAI instruction else it can only be interrupted by the non maskeble interrupt. There is something that you have be sure of: the WAI instruction can only do its...

And for the "oldy's" (I am one myself), a debugger that is not depending on single stepping hardware or debugging register is often written with the use of self modifing code. You can trace a programming by copying the code in a memory location add a ret to it and just call the memory location...

| void * p1 = 0x12345678; | __asm jmp 0x12345678; | |Ive failed, till now, to reach this objective. The |instruction __asm jmp dword ptr [p1], for example, |generate a "jmp mem16" (FF 65 F8) jump. Moreover, |why "__asm call p1" fail to reach the memory address |referenced by p1? __asm...

Sometimes push and puls in a main routine is used if you are not sure that the routines you call will save the registers in use that you want to use again for a next call. Also it is possible that the routine you are calling expects the values it uses are on the stack. In some operating...

As I wrote: you can't use three "register" as a index in one instruction. So don't correct me with a third index. An immedicate value can be seen as an index, but normally it is used as the base address of the array you want to index within. Tessa