Thankx for the post PC888! Everything you wrote seemed to make sense to me. Here is another cool work with Logarithmic and exponential functions that involves the modeling of internet hosts. I hope you enjoy.
[The modeling data may be off, but it was as accurate as it could get in 1999 ;) ]...
Actually I am not a student at all - I am self-taught and lack many skills when it comes to efficient programming.
However I must mention that the options in my form are grouped into seperate frames (three seperate frames, one for each textbox).
If you feel so inclined I would greatly...
Hello PC888, thanks for asking!
I was having the same question myself! The higher the coffee temperature, the shorter it would take the coffee to cool . . . that seemed way wrong to me also! I beleive this results because the constants in this logarithmic and exponential function calculation...
Actually I am not a student at all - I am self-taught and lack many skills when it comes to efficient programming.
However I must mention that the options in my form are grouped into seperate frames (three seperate frames, one for each textbox).
If you feel so inclined I would greatly...
Thank you all for your responses.
Below is my working code [and it works - wohoo! ;)]
Private Sub cmdCalculate_Click()
Dim sngT_Coffee As Single
Dim sngT_Ambient As Single
Dim sngTime As Single
If optT_Coffee_C = True Then
sngT_Coffee = (txtT_Coffee.Text) / (1) 'Keeps the celsius...
Thank you all for your responses.
Below is my working code [and it works - wohoo! ;)]
Private Sub cmdCalculate_Click()
Dim sngT_Coffee As Single
Dim sngT_Ambient As Single
Dim sngTime As Single
If optT_Coffee_C = True Then
sngT_Coffee = (txtT_Coffee.Text) / (1) 'Keeps the celsius...
I am still having a problem . . . [Grrrrr] ;)
Here is my code:
Private Sub cmdCalculate_Click()
Dim sngT_Coffee As Single
Dim sngT_Ambient As Single
'Dim sngTime As Single
If optT_Coffee_C = True Then
sngT_Coffee = (txtT_Coffee.Text) / (1) 'Keeps the celsius temperature inputted...
Actually PC888, I am coding in VB6. I am sorry for posting in VB.Net, but at the time I was unable to post a new thread in VB5&6!
But I am still having a problem . . . [Grrrrr] ;)
Here is my code:
Private Sub cmdCalculate_Click()
Dim sngT_Coffee As Single
Dim sngT_Ambient As Single
'Dim...
Sorry all!
I just needed to divide my solution with log(e)
Wohoo! Applied Learning!
Although I beleive Visual Basic should include a Natural Logarithm function!
Sorry all!
I just needed to divide my solution with log(e)
Wohoo! Applied Learning!
Although I beleive Visual Basic should include a Natural Logarithm function!
I understand how to calculate my problem and cancel out everything perfect while using the natural logarithm, but I am unfamiliar with substituting the LN with log because of the cancelation differences.
Code example:
txtTime.Text = LN((sngT_Coffee - sngT_Ambient) / (75)) / (-0.1)
Note for my...
I am sorry johnwm. I understand how to calculate my problem and cancel out everything perfect while using the natural logarithm, but I am unfamiliar with substituting the LN with log because of the cancelation differences.
Code example:
txtTime.Text = LN((sngT_Coffee - sngT_Ambient) / (75)) /...
I am having a difficult time finding information on how to use the Natural Logarithm in my Visual Basic v6.0 code. If anyone is familiar using the Natural Logarithm with Visual Basic, please give me a hand.
Here is my code example:
txtTime.Text = LN((sngT_Coffee - sngT_Ambient) / (75)) /...
How can I use the Natural Logarithm in my code? I am having a difficult time finding information on how to use the Natural Logarithm in my Visual Basic code.
If anyone is familiar with using the Natural Logarithm with Visual Basic, please give me a hand.
Here is my code example:
txtTime.Text...
Thanks again for your help with understanding the concept of option button logix. I have it nailed down and your help was solid. Thanks so much.
Here is the code to my fully working application! Thanks to your help my current and future applications will be much more flexible...
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