Recent content by FedoEx

Got it. $1!=0&&$2==0{ b[$3]-=$4;} $1==0&&$2==0{ b[$3]+=$4;} $1==0&&$2!=0{ b[$3]-=$4;print $3, b[$3] } It works for this particular case. I am still looking for alternative solutions.

Thanks. I could use that approach. The blocks are not necessarily 9 lines. It could change from one block to another. My bad I did not specify that. Still I believe I can use your approach . Will post back as soon as I get some solution.

I have four columns input data.x,y,z b,c,d are some numbers not necessarily the same. x 0 z1 bl x 0 z2 cl x 0 z3 dl 0 0 z1 bc 0 0 z2 cc 0 0 z3 dc 0 y z1 br 0 y z2 br 0 y z3 br The data could be separated in blocks of triplets for which the third column is the same. The sequence z1,z2,z3 would...

Yes. That is exactly what I need. Thanks a lot.

I need only the last line to end with ; All the rest should end with +.

Hope I am not deviating much from the thread promp Recently I had to setup a cronjob where periodically would copy the file over scp.The command portion of my cronttab looked something like that. /usr/bin/scp -i /home/user/.ssh/id_dsa /tmp/file.dat server.net:~/ If I were to execute the same...

Input file 1300483198 -4.60508 1300483199 -4.60825 1300483200 -4.60691 1300483201 -4.60581 1300483202 -4.60806 1300483203 -4.60747 1300483205 -4.60788 1300483206 -4.60704 1300483207 -4.60843 1300483208 -4.60675 1300483209 -4.60827 1300483210 -4.60721 1300483211 -4.60807 1300483212 -4.60778...

Thanks again feherke. The deisired output for regex1 regex2 would be 1 11 12 2 21 22 3 31 32 To explain. First value of each row is the block number. Values two three are the values of the fields right under the regex1 and regex2.

Thanks. My initial try was this. awk '{for(i=1;i<=NF;++i)if(match($i,/regex1/)); getline; print $i }' What I don't understand is why the /regex1/ outside the {...} block is needed. If you remove it awk should process that for loop inside the {...} for each line of the input file and yet if I...

simple example inputfile regex1 regex2 regex3 1 2 3 4 5 6 regex1 regex3 regex2 aa bb cc 7 8 9 If I want to print the next line after the regex2. In my inptut file awk '/regex1/{getline;print $0}' inputfile How can I print only the...

Find has an option to search for files older/newer than X days,hours,... find ABC* -mtime +3 -exec rm {} \; Removes the ABC* files older than 3 days.

try denyhosts http://denyhosts.sourceforge.net/ Adds ip's to //etc/hosts.deny after X number of unsuccessful login attempts for the period of the last Y days. Highly configurable with many options. or sshutout Blocks ip's on the iptables level...

www.linuxfromscratch.org/

Consider the input file where the last $2==y entries are consecutive. 1 y 10 2 y 11 3 y 10 4 n 12 5 n 22 6 y 12 7 y 12 8 n 33 9 y 12 10 y 10 11 y 10 12 y 10 13 y 10 14 n 12 Now the output of the the second code will give 1 2 3 6 - 7 9 10 The last line is missing...

Thanks feherke. $1 values are ascending integers from 1 to 1000.