XSLT

JontyMC · Nov 26, 2004

XML:

Code:

<doc>
  <metadata>data</metadata>
  <content>content</content>
</doc>

XSLT:

Code:

<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet version="1.1" xmlns:xsl="[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform">[/URL]
  <xsl:output method="html" />
  <xsl:template match="content">
    <html>
      <body>
        <p><xsl:value-of select="." /></p>
      </body>
    </html>
  </xsl:template>
</xsl:stylesheet>

In IE it displays "datacontent", whereas in firefox it displays "content", which is what I expected. Whats going on there?

Jon

3143 · Nov 26, 2004

Your template match is only the content

<xsl:template match="content">

Use instead of this

<xsl:template match="/"> referring to the hole file

Any help?

JontyMC · Nov 26, 2004

I only want to match the content, in reality my content has child elements. I dont want to have to keep referring to them by content/elementname. I only want to display the content.

Thanks for the effort though (ps hole is spelt whole in this context).

cfitzner · Dec 2, 2004

add this template:

<xsl:template match="/">
<xsl:apply-templates select="//content[1]"/>
</xsl:template>

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XSLT

JontyMC

Programmer

3143

Technical User

JontyMC

Programmer

cfitzner

Programmer

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