XSLT: Determing odd or even node count

[JoeMcGarvey]

Hi there....
Can anyone point me in the right direction here...

I am trying to write an xsl:if statement that checks if the node count is odd or even. If it is odd (say 1 or 3) it writes:

<tr><td>STUFF</td>

If it is even (say 2 or 4) it writes:

<td>STUFF</td></tr>

The result is a table with two <td>'s per row.

If anyone is familiar with the Mod function in VB, that's what I want to accomplish.

Thanks for any help!!

 

[JoeMcGarvey]

Got my answer...

<xsl:when test=&quot;position() mod 2 = 1&quot;>