XSL - check if child node exists

Kai77 · May 13, 2005

I have the following XML document:

<?xml version="1.0" encoding="utf-8" ?>
- <navigation>
<chapterlevel_1 title="Homepage" level="1" id="1747" active="1" breadcrumbmember="1" />
<chapterlevel_1 title="Profiel" level="1" id="1749" active="0" breadcrumbmember="0" />
- <chapterlevel_1 title="Producten & diensten" level="1" id="1751" active="0" breadcrumbmember="0">
<chapterlevel_2 title="Web Development" level="2" id="1755" active="0" breadcrumbmember="0" />
<chapterlevel_2 title="E-mailmarketing" level="2" id="1756" active="0" breadcrumbmember="0" />
- <chapterlevel_2 title="Search Engine Optimalisatie" level="2" id="1757" active="0" breadcrumbmember="0">
<chapterlevel_3 title="test" level="3" id="1766" active="0" breadcrumbmember="0" />
</chapterlevel_2>
<chapterlevel_2 title="On-line Brand Management" level="2" id="1758" active="0" breadcrumbmember="0" />
<chapterlevel_2 title="Website Management" level="2" id="1759" active="0" breadcrumbmember="0" />
</chapterlevel_1>
<chapterlevel_1 title="Shocases" level="1" id="1752" active="0" breadcrumbmember="0" />
<chapterlevel_1 title="Nieuwsbrief" level="1" id="1753" active="0" breadcrumbmember="0" />
<chapterlevel_1 title="Contact" level="1" id="1754" active="0" breadcrumbmember="0" />
</navigation>

How can I use the "if" statement to see whether a chapterlevel_1 has childnodes (chapterlevel_2)?

JontyMC · May 13, 2005

Code:

<xsl:if test="chapterlevel_1/*">.....

Jon

"There are 10 types of people in the world... those who understand binary and those who don't.

CubeE101 · May 13, 2005

or...

If you are looping through the nodes, and want to know if the current node has children...

Code:

<xsl:if test="./*">

Such as: (chapter.xsl)

Code:

<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet xmlns:xsl="[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform"[/URL] version="1.0">
  <xsl:variable name="tab">20</xsl:variable>
  <xsl:template match="/">
    <html>
      <body>
        <xsl:call-template name="recurse">
          <xsl:with-param name="tabs" select="0" />
          <xsl:with-param name="node" select="navigation" />
        </xsl:call-template>
      </body>
    </html>
  </xsl:template>

  <xsl:template name="recurse">
	  <xsl:param name="node"/>
	  <xsl:param name="tabs"/>
      <xsl:for-each select="$node/*">
	    <a STYLE="padding-left: {$tab * $tabs}"><xsl:value-of select="concat(@title,' (',@id,')')"/></a><br/>
		[b]<xsl:if test="./*">[/b]
          <xsl:call-template name="recurse">
            <xsl:with-param name="tabs" select="$tabs + 1" />
            <xsl:with-param name="node" select="." />
          </xsl:call-template>
		</xsl:if>
      </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

Then, you don't even need to use the level_x...

Code:

<?xml version="1.0" encoding="utf-8" ?> 
<?xml-stylesheet type="text/xsl" href="chapter.xsl"?>
<navigation>
  <[b]chapter[/b] title="Homepage" level="1" id="1747" active="1" breadcrumbmember="1" /> 
  <[b]chapter[/b] title="Profiel" level="1" id="1749" active="0" breadcrumbmember="0" /> 
  <chapter title="Producten [b][COLOR=red]&amp;[/color][/b] diensten" level="1" id="1751" active="0" breadcrumbmember="0">
    <chapter title="Web Development" level="2" id="1755" active="0" breadcrumbmember="0" /> 
    <chapter title="E-mailmarketing" level="2" id="1756" active="0" breadcrumbmember="0" /> 
    <chapter title="Search Engine Optimalisatie" level="2" id="1757" active="0" breadcrumbmember="0">
      <chapter title="test" level="3" id="1766" active="0" breadcrumbmember="0" /> 
    </chapter>
    <chapter title="On-line Brand Management" level="2" id="1758" active="0" breadcrumbmember="0" /> 
    <chapter title="Website Management" level="2" id="1759" active="0" breadcrumbmember="0" /> 
  </chapter>
  <chapter title="Shocases" level="1" id="1752" active="0" breadcrumbmember="0" /> 
  <chapter title="Nieuwsbrief" level="1" id="1753" active="0" breadcrumbmember="0" /> 
  <chapter title="Contact" level="1" id="1754" active="0" breadcrumbmember="0" /> 
</navigation>

Either way should work...

Also, don't forget to use '&' instead of '&'

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XSL - check if child node exists

Kai77

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JontyMC

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CubeE101

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