WorkFlow and LAPI

[hanreb]

Hi,

Can I set the Assignee in a Workflow step using LAPI ??

Thanks,
Sunu

 

[appnair]

isn't it called reassign task ?

Well, if I called the wrong number, why did you answer the phone?
James Thurber, New Yorker cartoon caption, June 5, 1937

 

[hanreb]

Yes it is ReassignTask(). That's what I found in the API doc. But I was unable to reassign a user.
Do u have any code for the same.

I will reevaluate my code and post it.
If you could let me know where I am going wrong.

Thank You,
sunu

 

[appnair]

no i don't have any code

Well, if I called the wrong number, why did you answer the phone?
James Thurber, New Yorker cartoon caption, June 5, 1937

 

[hanreb]

To use the ReAssignTask API first I am trying to get a list of the tasks.

But I get the error
com.opentext.api.LLUnknownFieldException: LLValue unknown field name: SubWorkTask_TaskID

I used ListTaskStatus as below
//Get the Workflow ID
LLValue workID = (new LLValue()).setAssocNotSet();

//Start the workflow using the map

if(wf.StartWorkflow(map, "Name of New Workflow", additions, workID) != 0)
{
System.out.println("StartWorkflow Failed.");
}
else
System.out.println("Workflow Initiated. The new workflow's ID is " + workID);
int wid= workID.toInteger();
System.out.println("wid is "+ wid);

LLValueEnumeration enumeration;
LLValue tasks = (new LLValue()).setTable();

int status=wf.ListTaskStatus(wid, 0, 0, tasks);
enumeration = tasks.enumerateValues();

System.out.println("status is "+status);
while (enumeration.hasMoreElements())
{
LLValue currentRec = enumeration.nextValue();


System.out.println("Task id is "+ currentRec.toInteger("SubWorkTask_TaskID"));


Could you please help...

Thank You,
sunu

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