Hi,
I have the follwoing problem. I am creating a c code .exe of the following differential eqaution problem (not yet create)
dh(t) = -c/2gh(t) + 1
----- --------- ------u(t)
dt A(h(t)) A(h(t))
on the first line the / in -c/2gh(t) represents a square root over 2gh(t).
This differential equation represents a surge tank, and the problem is, that i need to have a .exe, to link in to a visual basic program, that will then show results if the flow into the tank changes etc.
The following information is necessary:
where u(t) is the input flow (control input). h(t) is the liquid level (output of plant). A(h(t)) is the cross-sectioanl area of the tank. g = 9.8m/sec squared. c = 1, known cross-sectional area of the output pipe. let r(t) be the desired level of the liquid in the tank ( the reference input)
And I need to figure out how to send an input to the .exe and read an output from it. I have some basic knowledge of VB, but not enough to do this. If anyone could help me with this, I would be extremely gratefull.
Thanks,
Joseph Quinn
I have the follwoing problem. I am creating a c code .exe of the following differential eqaution problem (not yet create)
dh(t) = -c/2gh(t) + 1
----- --------- ------u(t)
dt A(h(t)) A(h(t))
on the first line the / in -c/2gh(t) represents a square root over 2gh(t).
This differential equation represents a surge tank, and the problem is, that i need to have a .exe, to link in to a visual basic program, that will then show results if the flow into the tank changes etc.
The following information is necessary:
where u(t) is the input flow (control input). h(t) is the liquid level (output of plant). A(h(t)) is the cross-sectioanl area of the tank. g = 9.8m/sec squared. c = 1, known cross-sectional area of the output pipe. let r(t) be the desired level of the liquid in the tank ( the reference input)
And I need to figure out how to send an input to the .exe and read an output from it. I have some basic knowledge of VB, but not enough to do this. If anyone could help me with this, I would be extremely gratefull.
Thanks,
Joseph Quinn
