variable in pattern match

[cp2000]

I have what appear to be to issues I need to resolve.
1) I need to be able to pass a variable to the pattern match.
e.g awk -F" " '/v1/ {print $3,$4,$5,$6,$7}'v1=$RDSK dumpdates where RDSK="c0t2d0s0 0"

2) As you see my variable (RDSK) has a number spaces in it.

 

[olded]

Hi:

Read grega's pass variables to awk FAQ:

forum271

Try placing double quotes around your variable:

v1="$RDSK"

Regards,

Ed

 

[PHV]

Try something like this:

RDSK="c0t2d0s0               0"
awk -F" " "/$RDSK/"'{print $3,$4,$5,$6,$7}' dumpdates

Hope This Help
PH.

 

[CaKiwi]

Or

awk -F" " -v v1=$RDSK '$0 ~ v1 {print $3,$4,$5,$6,$7}' dumpdates


CaKiwi

"I love mankind, it's people I can't stand" - Linus Van Pelt

 

[cp2000]

Thanks peoples...got it working.

olded: I actually started by doigna keyword search and reading the Variable FAQ. That was my adaptation of the examples.

PHV: I'm notsure I understand why the double-quotes on the pattern makes the difference but IT WORKS like a champ...THANKS!!!

CaKiwi: That's like what I would expect to work but.....
-bash-2.05b# awk -F" " -v v1=$RDSK '$0 ~ v1 {print $3,$4,$5,$6,$7}' dumpdates
awk: cmd. line:2: fatal: cannot open file `$0 ~ v1 {print $3,$4,$5,$6,$7}' for reading (No such file or directory)