Variable as default value within Menu 1

RENO9 · Jan 20, 2006

I have a form starting with a drop down menu i.e.

Code:

<select name="gangs" onchange="submit()">
     <option value="">Select Gang...</option>
     <option value="A1">HanA - Shop 1</option>
     <option value="A2">HanA - Shop 2</option>
     <option value="B1">HanB - Shop 1</option>
     <option value="B2">HanB - Shop 2</option>
</select>

when a choice is selected the form submits itself back onto the same page and registers the choice as a variable

Code:

$GangNumber = $_POST['gangs'];

the problem is that i want to show the variable as the default choice in the drop down menu when the user continues the form rather than reverting back to "Select Gang..." (As this causes it to lose the variable when the form is submitted again)
I have tried various ways but to no avail i.e.

Code:

selected="<? echo $GangNumber; ?>"

Any suggestions?
Thanks in Advance

Vragabond · Jan 20, 2006

The way to do it is to add [tt]selected="selected"[/tt] to the option you want selected. So if it is the third option, then add that statement to the third option. This is of course easily done with a simple if clause: if the value from post matches the value I am outputing, then add the attribute. If not, skip to next. How you will do it in your code, I don't know. You can just add this check for every line or store all the values in the array and loop through the array checking values all the way.

sleipnir214 · Jan 20, 2006

You have to loop through the options, and output the word "selected" as part of the <option> tag when the value of the option matches your input.

Something like:

Code:

<?php

print '<html><body>';

print '<form method="POST" action="' . $_SERVER['PHP_SELF'] . '">';
if (isset($_POST['gangs']))
{
	$gangs = $_POST['gangs'];
}
else
{
	$gangs = '';
}

$gangs_array = array
(
	'A1' => 'HanA - Shop 1',
	'A2' => 'HanA - Shop 2',
	'B1' => 'HanB - Shop 1',
	'B2' => 'HanB - Shop 2'
);

print '<select name="gangs" onchange="submit()"><option value="">Select gang...</option>
';

foreach ($gangs_array as $value => $display)
{
	print '
	<option value="' . $value . '"';
	if ($gangs == $value)
	{
		print ' selected ';
	}
	print '>' . $display . '</option>';
}

print '<br/><input type="submit"></form></body></html>';

?>

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RENO9 · Jan 23, 2006

Thanks sleipnir214 for the code, i just added the select closing tag </select> at the end and it worked fine with the rest of the page.

Thanks

sleipnir214 · Jan 23, 2006

Oops. Sorry about that. My code was standalone, so I didn't see that error.

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Variable as default value within Menu 1

RENO9

Technical User

Vragabond

Programmer

sleipnir214

Programmer

RENO9

Technical User

sleipnir214

Programmer

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