Var 11 auto converted to 13

[Zhris]

Hello,

Every time I use a query param with the value 11 or 2011, its automatically converted to 13 or 2013. In fact anything below 12 or 2012 is converted. Example:

// /test.php?Year=11

<?php
	$year = $_GET['Year'] | '12';
	echo "$year";
?>

I'm assuming its recognizing that the value is a date that has passed. Why would it do this / how to I go about resolving it.

Thanks,

Chris

 

[Zhris]

Quick update. I'm getting varying results typing different numbers in as the value. Absolutely no idea why.

 

[Zhris]

Last update. Looks like its to do with my method of using the 'or' operator to ensure the value defaults to "12". My question is then, how do I set a default value in one line.

Thanks,

Chris

 

[vacunita]

The comparison operator is 2 pipes || not one. What you are doing there is the bitwise 'OR' operation of your value and 12.

$a | $b Or (inclusive or) Bits that are set in either $a or $b are set.

What you want to use is a ternary operator or inline conditional.

$result = action ? value : else;

If action is true value is set, otherwise the else part is set, so:

  $year = [red]isset([/red]$_GET['Year'][red])[/red] [blue][b]?[/b][/blue] $_GET['Year'] [blue][b]:[/b][/blue] '12';

http://mx.php.net/manual/en/language.operators.comparison.php

----------------------------------
Phil AKA Vacunita
----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

Web & Tech

 

[Zhris]

Hi vacunita,

Thanks alot, that did the trick.

Chris

 

[vacunita]

Glad I could help.

----------------------------------
Phil AKA Vacunita
----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

Web & Tech