using grep to search in a field

[jalge2]

I have a file. The file contains different information all separated by a comma. In the 8th field it either says prt8 or prt9. I want to grep for the 8 or the 9 in the 8th field. How do I do this?

 

[CaKiwi]

You could use awk

awk -F, '$8 ~ /prt8/' file-name
awk -F, '$8 ~ /prt9/' file-name
awk -F, '$8 ~ /prt[89]/' file-name


CaKiwi

"I love mankind, it's people I can't stand" - Linus Van Pelt

 

[vgersh99]

to output all records with the eight field containing '9':
nawk -F, -v f="8" -v v="9" '$f ~ v' myFile.txt

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[dickiebird]

Awk is your friend :
Try this (untested)

awk -F&quot;,&quot; '$8==&quot;prt9&quot;||$8==&quot;prt8&quot; {print}' yourfile

HTH


Dickie Bird (-)))

 

[bigoldbulldog]

awk -F&quot;,&quot; '$8 ~ /[89]/'

Cheers,
ND

bigoldbulldog@hotmail.com