Using cut to count files

[jestrada101]

How can I cut a variable to just show me the first part of the variable?

example... i could have the following..

a.g.d.a.g
b.b.dl.s.a.g
l.li.w.s.g.g
l.d.d.g

I only want the "g" returned? Can "cut" somehow work backwards to only remove teh last field....

Thanks
JE

 

[Chapter11]

ugly way of doing it, I'm not a sed or awk guru:

basename `echo "b.b.dl.s.a.g" | tr "." "/"`

 

[jestrada101]

Thanks..
but I would like the "g" stripped out... and be given everything prior that that..
from:
b.b.dl.s.a.g
to
b.b.dl.s.a


THANKS!

 

[vgersh99]

sed -e 's/\(.*\)\.g/\1/' myFile.txt

or if dealing POSIX shells:

a='b.b.dl.s.a.g'
b="${a%%.g}"

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[aigles]

With base name :

basename 'a.b.c.d' .d

Anothers solutions like vgersh99 solution but more general :

sed -e 's/\.[^*]$//'

aaa.bbb.ccc -> aaa.bbb
aaa.bbb. -> aaa.bbb

With Posix shell :

${a%.*}


Jean Pierre.

 

[aigles]

oups!

sed -e 's/\.[^.]$//'



Jean Pierre.

 

[jestrada101]

Thanks all.