Using command line arguments

[Cbasic]

How do you:<br>
<br>
Write a program that accepts several arguments from the command line and based on these arguments perform none or several different operations on the specified input file.<br>
<br>
For eg.<br>
<br>
A command such as:- "Comline.exe inputfilename.ext outputfilename [/v /u /s]"<br>
<br>
/v - Counts the amount of vowels in the text file<br>
<br>
/u - Converts the entire text file to capitals letters<br>
<br>
/s - Sorts the words(including numbers and special characters) of the input file in alphabetical order and save the sorted version in a file called "result.s".<br>
<br>
The program should also produce three output files:<br>
/v - result.v<br>
/u - result.u<br>
/s - result.s

 

[MikeLacey]

So - is this a college assignment then?

 

[Cbasic]

No is it not a college assignment but I presently doing a course for the job I am presently working at. Can you help me??????? Please!!!

 

[MikeLacey]

About 90% of the stuff you need to know to do this is covered in the book "The C Programming Language" by Kernigan and Richie. That should sort you out.<br>
<br>
Could I suggest you treat the excersise as three separate programs? Complete each and then combine the programs into one at the end.<br>
<br>
Get the book - or the Nutshell book "Practical C" - and make a start. When you hit a problem - get back to us. <br>
<br>
We're more than willing to help but it's easier to help with very specific problems rather than a "How do I write a program that..." sort of question.<br>
<br>
Email me with any specific queries if you'd rather but remember that most people who use discussion groups like this don't actually post anything - they just read everything. So it's more useful to post queries - then everyone can see the answers.<br>
<br>
Regards<br>
<br>
Mike<br>
---<br>
Mike_Lacey@Cargill.Com<br>

 

[DarkOrk]

The reason you probly don't know how to write a command line program is because you only know that main() is just main()... You probly havn't found out that there are arguments passed to it. <br>
<br>
By now, a few days down the road you probly have found this information. But others may have not. So:<br>
<br>
int main (int argc, char* argv[])<br>
<br>
argc is the number of parameters passed<br>
argv is everything that was passed split into an array of strings <br>
<br>
The variable names can be changed to whatever you want, but they have to be those types. I have seen argv be a char** before, but don't remember where from.<br>
<br>
Hope this helps

 

[ssingh]

You've to take the command line arguments in argv(). The arguments are separated by a blank space. And the number of argument is stored in argc. The main complexity is in the last argument. Better if you pass it by separating with a space. Or else the last arguments need to be checked for the speacial character like '/'. <br>
<br>
Pseudocode. <br>
<br>
1) Check for the last argument . If it contains '/'. <br>
2) If yes then count the number of '/'. <br>
3) According to the argument , you need to produce that many output files.<br>
<br>
Does it answer your question ?<br>
Thanx<br>
Siddhartha Singh<br>
<A HREF="mailto:ssingh@aztecsoft.com">ssingh@aztecsoft.com</A>