using 'char' variable 1

[MarkJ2]

I am writing a program using classes. In the header file I want to declare a 'char' variable as private (lets call the variable 'flag'). Then in the member class function 'print' depending on whether the time is 0 thru 11 or 12 thru 23 ( I am using military time) I want the 'char' variable 'flag' to hold the string either 'AM' or 'PM'.

Once I am in the 'print' function I am not sure how to assign either 'AM' or 'PM' to the char variable. Is it..
flag = "AM" or flag == "AM" or flag == 'AM'.
I have tried several different ways and nothing is working.

Thanks

 

[vkarthik]

hi

u cannot assign a string to a char. do the following.

have that flag as a char array and not char.

char flag[3];

to assign some value to it, do this,

strcpy(flag,"AM" (to copy AM or PM to flag).

to check if it is AM or PM, do this,

strcmp(flag,"AM" (this will return zero if the string are equal or a non zero value).

hope this helps. feel free to write again if it's not clear.

luv
Karthik.

 

[chiph]

MarkJ -

Like Karthik implies, you need to reserve storage for the "AM" or "PM" string, plus a 0 to terminate the string. If you use a variable of type char (not an array of char), it can only hold 1 character and can't participate in any string functions. If you create a 3-character array it then becomes a two-character string, and you can concatenate it, etc. using the standard C str functions.

Chip H.