URL + Path 2

[vlitim]

if the browsers address is

http://wwww.testDomain.co.uk/default.asp?step=4&pid=5

how do I get the

/default.asp?step=4&pid=5

part

 

[CodeFish]

Hi vlitim,

Try:-


Dim sURL
Dim lPos
Dim sString

'Get Page URL
sURL = Request.ServerVariables("URL&quot

'Get Position of Last "/"
lPos = InStrRev(sURL , "/&quot

'Get String Segment out of URL
sString = Mid(sURL , lPos , Len(sURL))


Hope This Helps,

Codefish

 

[lobstah]

that will get you up to the ?. to get the querystring portion (step=4&pid=5) you need to use:

sQuery = Request.ServerVariables("QUERY_STRING&quot

so your complete string would be:

sString = Mid(sURL , lPos , Len(sURL)) & "?" & Request.ServerVariables("QUERY_STRING&quot