Unicode character Comparision Problem

[pratham123]

Hello friends
i got a problem for unicode character comparision problem.actually i want to check particular character is exist in the string or not.
here i m sendning a code just check and send me suggestion how to check it

set of unicode character.
static String chUnicode[] = { "\uE640", "\uE641","\uE63E",
"\uE642", "\uE643", "\uE644", "\uE645", "\uE646", "\uE647", "\uE648", "\uE64A", "\uE64B", "\uE64C", "\uE64D", "\uE64E", "\uE64F", "\uE651", "\uE652", "\uE653", "\uE654", "\uE655", "\uE656", "\uE657", "\uE658", "\uE659", "\uE65A", "\uE65B", "\uE65C", "\uE65D", "\uE65E", "\uE65F", "\uE660", "\uE661", "\uE662", "\uE663", "\uE664", "\uE665", "\uE666", "\uE667", "\uE668", "\uE669", "\uE66A", "\uE66B", "\uE66C", "\uE66D"};


public static boolean isImageCharacter(String strSource)throws UnsupportedEncodingException{
//String strSrc = new String(strSource.getBytes("UTF-8"),"UTF-8");
byte byteName[] = strSource.getBytes("UTF-8"); // ----Checking Each Character
String strByte1 = null;
String strByte2 = null;
// -------------
for (int nCountName = 0; nCountName < byteName.length; nCountName += 2) {
strByte1= byteToHex(byteName[nCountName]);
strByte2= byteToHex(byteName[nCountName+1]);
// -----Checking UNicode Array-----
for (int nCount = 0; nCount < chUnicode.length; nCount++){
byte byteReserve[] = chUnicode[nCount].getBytes("UTF-8");
String strImage1 =byteToHex(byteReserve[0]);
String strImage2 =byteToHex(byteReserve[1]);

if (strByte1.equals(strImage1) && strByte2.equals(strImage2)) {
return false;
}
}
}
return true;
}

public static String byteToHex(byte b) {
// Returns hex String representation of byte b
char hexDigit[] = {
'0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'a', 'b', 'c', 'd', 'e', 'f'
};
char[] array = { hexDigit[(b >> 4) & 0x0f], hexDigit[b & 0x0f] };
return new String(array);
}

public static String charToHex(char c) {
// Returns hex String representation of char c
byte hi = (byte) (c >>> 8);
byte lo = (byte) (c & 0xff);
return byteToHex(hi) + byteToHex(lo);
}







thnx in advance
regards
Alpesh