Unexpected T_STRING? Eh..

[BittenApple]

It says unexpected T_STRING in line 9, but I dont get it, whats a string? I read a tutorial on reading errors, but it say T_'then problem of name' but I dont know what a string is..
this is my line 8-10

8  //Start table
9  echo "<table width="100%">
10 "

Heh, I know the "100%" is wrong, because it must include some slashes, but i've tried with/without 'em.. anyone can to help?

O, and btw, is there a program that checks any errors in the program - I tried PSPAD and PHP CODER PRO! but none of them seem to do it..

Thanks guys, you'r all big helps!!

 

[Vragabond]

When you use quotes within qoutes you should escape them:

echo "This is a \"string\"";

Backslash is used as an escape character here. Alternatively, php supports both single and double quotes around strings. As such, you can use single quotes for html strings to make them more readable.

echo '<table width="100%">';

This will work beautifully.

 

[sleipnir214]

You're trying to use doublequotes inside of doublequotes. PHP is interpreting this is as:

echo the string "<table width=", then
the bare string 100%, then
the string ">"

and it doesn't know what to do with the bare string 100%.

You must either escape the interior doublequotes:

echo "<table width=\"100%\">
";

or use doublequotes within singlequotes:

echo '<table width="100%">
';

I prefer the latter, as it makes the script more readable. There are differences in the behavior of the two quotes and how interior variable references are handled. See

http://www.php.net/manual/en/language.types.string.php

for more information.


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[BittenApple]

Wow thanks, it seems to be working..

But, now its turned into a T_LNUMBER -- :S

echo '<table width="100%">';

thats what it is - whats a LNUMBER?

 

[kenrbnsn]

What are the lines before this one. Sometime the parser won't put out a messages until it can't figure what anything means.

Ken

 

[sleipnir214]

Post your entire script (or at least the entire script up to this line. Also post the exact error message.


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[BittenApple]

<?php
function shoutView(){
$color1 = "#466A2B";
$color2 = "#568434";
$e_shout = mysql_query("SELECT FROM 'shoutbox');
echo '<table width="100%">';

I edited loads of lines, so now the problem is on line 6.. heh. Btw, ''db.php'' in included in index.php, and this file is included in index.php so theres no problem connecting to database..

Error:

Parse error: parse error, unexpected T_LNUMBER in ''not to be shown'' on line 6

 

[MJB3K]

i just do this:

echo "<table width=100%>";

works for me

Regards,

Martin

Gaming Help And Info:

http://gaming.webrevolt.biz

 

[sleipnir214]

One problem I see is with this line:

$e_shout = mysql_query("SELECT FROM 'shoutbox');

You're not closing your outermost quotes. The line should read:

$e_shout = mysql_query("SELECT FROM 'shoutbox'[red]"[/red]);


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[BittenApple]

Haha, thank you so much sleipnir. I feel like such an idiot!!

 

[sleipnir214]

Parse error" is PHP's way of saying, "Hold on, I'm confused."

With that in mind, it's important to remember that the line number PHP gives in a parse error is not the line where the actual error will reside, but rather the line at which PHP realizes is is confused. The two can be, but are not necessarily, one and the same. In my experience, the line with the actual error most often falls before the line which PHP reports.



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[MJB3K]

you should put or die(mysql_error()) after queries if you want it to display an error if it goes wrong!

Regards,

Martin

Gaming Help And Info:

http://gaming.webrevolt.biz

 

[MattNeeley]

A nicer way to handle errors is actually to check after the line if it errored. That way you can control how the error is handled better then just stopping the script and telling the user possibly the information they need to circumvent some of your programming.

$sql = mysql_query("SELECT * FROM `none`");
if (!$sql) {
   //Handle Error Here
} else {
   //Use this for your normal execution or put die(); under the previous condition
}