im having problems using the TYPE function, i went to the help file to see how to use it but i keep getting errors
Cant i use
If TYPE(activecell.value) = 2 then.......
what is the proper syntax to determine whether my value is a string or not?? thanks!
Yea Zanthras I went back to the help function, saw the topic on TypeName, and tested it, and it worked, i wonder why it said TYpe would do that and it didnt help me. Thanks alot though, your always a great help!
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