trying to get awk to read just part of a line 1

[danclark]

This may sound rather dumb, but I am trying to just get awk to list whats after 'x word' until 'y word'...

eg...
[1055803211] SERVICE;

http://www.xeroxdirect.co.nz;HTTP;OK;1/3;

I want it to tell me what comes after HTTP but stop after the next ';'

HTTP;OK is all I need (or just OK)

I tried using the character number in the line but the first [1055803211] part keeps changing size.

 

[vgersh99]

match($0, /HTTP *;/) {
print substr($0,RSTART+RLENGTH, index(substr($0, RSTART+RLENGTH),";&quot-1)
}



vlad
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