trying to check if $* contains a *

[Larshg]

Hi

I trying to check if the parameters given to my scrip contains

tyed some thing like this(and numerus variations - with "" and ')
echo $*|grep '*'|wc -l


Larshg

 

[aigles]

To test if parameters contain a character '*', you can do :

[tt]if echo "$*" | grep -q '*'
then echo "'*' found"
else echo "'*' not found"
fi[/tt]

Another solution with bash and ksh :

[tt]if [[ "$*" = *\** ]]
then echo "'*' found"
else echo "'*' not found"
fi[/tt]



Jean Pierre.

 

[PHV]

Another way:
case "$*" in
*\**) echo "almost one '*' found";;
*) echo "no '*' found";;
esac

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[Ghodmode]

Just escape the asterisk. [tt]grep[/tt]'s argument is just a regular expression.

#!/bin/ksh

CHECKSTARS=`echo "$*" | grep "\*" | wc -l`

if [ $CHECKSTARS -gt 0 ]
then
    echo "There be stars, but no green clovers, blue diamonds, or purple horseshoes"
fi

--
-- GhodMode

 

[jad]

echo "$*" | tr -cd '\*' | wc -c

would tell you the number of stars explicitly