Trapping a character input on a double with cin

[Guest_imported]

I have a program that is expecting a double from a cin statement. I want to make sure it doesn't go into an infinite loop if someone enters a character instead. I am just starting at C++ in school. Thanks.

 

[Guest_imported]

while(TRUE)
{
cout << &quot;\nEnter an integer: &quot;;
cin >> i;
if(cin.good()) // if no errors
{
cin.ignore(10,'\n'); // remove newline
break; // exit loop
}
cin.clear(); // clear error bits
cout << &quot;Incorrect input&quot; << endl;
cin.ignore(10,'\n'); // remove newline
}
cout << &quot;Integer is &quot; << i << endl; // echo error free int


The above is for an int but works for doubles, float, and long double. You just need to check the goodbit (TRUE if all is OK).

Brother C