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[BIS]

Hello,

Can I use the tr command to translate the date format?

Suppose I have a file "date". The contents are only this:

09/12/2002

Can I use the tr command to change this to:

12-09-2002

If so, could somebody point me in the right direction? Any help much appreciated. As you can see this is a date, and it will be changing daily. Is there a way to make tr see that this is a date and change the format?

Or should I be using a different tool alltogether?

 

[dickiebird]

tr is fine for your needs; try :
date|tr "/" "-"

HTH ;-) Dickie Bird
db@dickiebird.freeserve.co.uk

 

[olded]

Bis:

tr does the separator as dickie has shown, but it looks like you're also needing to swap fields 1 & 2. Either modify the command that creates your date output of do something like this:


echo "09/12/2002"|awk ' BEGIN { FS="/" }
{
print $2"-"$1"-"$3
} '

Regards,

Ed

 

[jamisar]

dickiebird's solution is OK, just a typo
(supposed date is a file)
cat date | tr '/' '-'
don't forget in unix you have different way to do the same
sed -e 's/\//-xxx-/g' date
you get
12-xxx-09-xxx-2002


------------ jamisar
Einfachheit ist das Resultat der Reife. (Friedrich Schiller)
Simplicity is the fruit of maturity.

 

[DSMARWAY]

hi,

why don't you just use date to format the date i.e.

date +%d"-"%m"-"%y > filename

thats is day month year format

hth

 

[BIS]

Thank you all, using the date to format is what I will be going.

If I do date +%d"-"%m"-"%y > filename

my file will look like

17-09-02

is there a way to make it a four digit year

17-09-2002 ?

 

[vpshriyan]

Bis,

just upshift the year part.

date +%d"-"%m"-"%Y

 

[BIS]

sometimes life is all too easy.

Thank you.