Transfering most recent file every time from an directory 1

[gargamel100]

HI all,

I need your help if someone can can help

In an directory I have

-rw-r--r-- 1 ggggg ggggg 196846 2007-04-04 19:46 rrrrr_20070404214503_44538.txt
-rw-r--r-- 1 ggggg ggggg 192037 2007-04-04 20:02 rrrrr_20070404220002_44539.txt
-rw-r--r-- 1 ggggg ggggg 182503 2007-04-04 20:16 rrrrr_20070404221503_44540.txt
-rw-r--r-- 1 ggggg ggggg 162382 2007-04-04 20:32 rrrrr_20070404223003_44541.txt
-rw-r--r-- 1 ggggg ggggg 168154 2007-04-04 20:46 rrrrr_20070404224502_44542.txt
-rw-r--r-- 1 ggggg ggggg 161118 2007-04-04 21:02 rrrrr_20070404230002_44543.txt
-rw-r--r-- 1 ggggg ggggg 151536 2007-04-04 21:16 rrrrr_20070404231502_44544.txt

using this
ls -l | awk '{if ( $8~/^ggggg/ ) print $6 "\t" $7 "\t" $8 }'
I can filter date, time and filename. Every 14 min from one machine, and every 16 min from other machine I got new file, as above, but time stamp is different, part 21:02, 21:16 and so on. I need to find out some solution how transfer most recent file from this directory to another machine using ftp. FTP implementation is not problem,and when I write script I will put it in cron table to run every 20 min and fetch last file transfered to that directory. But I can not realise my how select last recent file, in directory, because time parameter is changing every time the file is transfered to this directory. If anybody has some hint to direct, it would be very helpful.
I can use awk and shell scripting tools.

best wishes and regards

Gargamel100

 

[hoinz]

Not sure if I fully understood your requirements...
I think you are looking for a way to find the newest file in a directory, right?

Well, this is awk forum, but I wouldn't use awk for this part.
What about this:
ls -rtl | tail -1

regards