time and date as double based on 1900 date system

[skibum019]

How do I get the current date and time and format it as a double based on the 1900 date system used in many programs such as MS Excel, etc.?

 

[ronnyjljr]

Here is what I use:

[blue]
int getDateInfo(int option)
{
struct tm *tm_struct;
time_t tm_num;
time(&tm_num);
tm_struct=localtime(&tm_num);
int a=tm_struct->tm_mon+1; [green]//MONTH[/green]
int b=tm_struct->tm_mday; [green]//DAY[/green]
int c=tm_struct->tm_year+1900; [green]//YEAR[/green]

if (option==1) return a;
if (option==2) return b;
if (option==3) return c;
return 0;
}
[/blue]

[green]I forgot why I put the 1900 on the year but I do belive it takes the difference between the current year and 1900, so you would get 104 instead of 2004[/green]

Hope that helps,
-Ron

cout << "If you don't know where you want to go, we'll make sure you get taken";