three boolean variables convert into string

[navrsalemile]

Hi all,

I have three boolean variables:

boolean flag1;
boolean flag2;
boolean flag3;

I want to represent them as octal number and convert this octal number into integer represented as String, i.e. if flags are:

flag1 is true
flag2 is false
flag3 is true

then String should be "5" which is binary 5 (0b101).

I came up with:
String suffix = Integer.toString((int)(flag1 ? 1 : 0) << 2 | (int)(flag2 ? 1 : 0) << 1 | (int)(flag3 ? 1 : 0));

but wonder if there is shorter more elegant solution?
many thanks,
mile

 

[timw]

Er, what's octal got to do with it? Octal is Base 8.

From your post, it looks like you want to interpret a collection of booleans as a binary value and calculate the corresponding integer value represented as a String.

Off the top of my head, I can't think of a shorter solution than yours.

Tim
---------------------------
"Your morbid fear of losing,
destroys the lives you're using." - Ozzy

 

[Diancecht]

If you really want if octal:

[/code]

String suffix = Integer.toString((flag1 ? 1 : 0) +(flag2 ? 2 : 0) + (flag3 ? 4 : 0));

It isn't more ellegant, but shorter and possibly faster (didn't test it).

Cheers,

Dian

 

[timw]

But anyway, a three digit binary number has a decimal range of 0 to 7, which is identical to its Octal representation since it never reaches 8 (10 in octal).

Tim
---------------------------
"Your morbid fear of losing,
destroys the lives you're using." - Ozzy

 

[Diancecht]

That's true.

If not, he'd need yo use the Integer.toString(num,8).

Cheers,

Dian