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The tomcat parameters

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azadehhomayoun

Programmer
Dec 11, 2006
1
FR
Hi
I am new using apache so maybe my question sounds stupid.
My program gets tomcat exception so i have been told to put this command on the line of start of the server, but I have no idea where shall I put it and how .can someone help:(I know my problem sounds stupid, but believe me , I am new)


$JAVACMD $TOMCAT_OPTS -Djme.db.protocol.sybase.driver=com.sybase.jdbc2.jdbc.SybDriver -Djme.db.protocol.oracle.driver=oracle.jdbc.driver.OracleDriver -Djme.db.protocol.mssql.driver=com.microsoft.jdbc.sqlserver.SQLServerDriver -Djme.db.protocol.sybase.interface=file:/DBAP02/dbaapp/clients/sybase/v12.5/interfaces -Djme.db.protocol.oracle.tnsnames=file:/DBAP02/dbaapp/clients/oracle/v8.1.7/network/admin/tnsnames.ora -Djme.db.protocol.mssql.interface=file:/DBAP02/dbaapp/clients/sybase/v12.5/interfaces -Dtomcat.home=${TOMCAT_HOME} org.apache.tomcat.startup.Tomcat "$@" &




thanks in advance
 
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