The php code does not display jpegs in sequence 1

[amir4oracle]

The code below is written to display jpegs on abc.com of the type:
is.100.jpg to is.110.jpg

<?php
for ($i=100; $i <= 110; $i++)
echo "<img src=\"

http://www.abc.com/is.\"$i\".jpg>";

?>

but it only shows the red x instead of the image.
What can be done to fix this problem?
Your help is highly appreciated.
Thanks in advance
Amir Khan

 

[vacunita]

IF I run that piece of code, it prints out:

<img src="[URL unfurl="true"]http://www.abc.com/is.[/URL][red]"[/red]100[red]"[/red].jpg>

I'm guessing those double quotes are not supposed to be there.

Try instead:

echo "<img src=\"[URL unfurl="true"]http://www.abc.com/is"[/URL] . $ i. "jpg>";

----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

 

[vacunita]

disregard previous code post. in reality is should be:

echo "<img src='[URL unfurl="true"]http://www.abc.com/is[/URL][red]." . [blue]$i[/blue] . ".[/red]jpg'>";

As i'm guessing you need the "." periods between is and $i variable and $jpg.

----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.

 

[amir4oracle]

I did the the following:

echo "<img src='

http://www.abc.com/is."

. $i . ".jpg'>";

but its still giving red x's, can you please tell me what mistake am i making here?

 

[amir4oracle]

now its working. Thank you so much.

 

[vacunita]

You are welcome. Glad I could help.

----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.