Terminate Unix script after 12 hours

[zen2003]

How do I write a script to terminate in 10 hours if a file is not found.
The script has to check for a file, if file not found go to sleep for 1 hour, check again....sleep....
If file not found even after 12 hours, then exit with error

thanks for your help

 

[tikual]

x=0
while (( $x < 12 ));
do
if [[ ! -f yourfile ]];
then
echo &quot;your file not found&quot;
sleep 3600
else
echo &quot;your file found&quot;
#if you don't want to exit, then comment &quot;exit&quot; and then add command 'sleep 3600' also.
exit
fi
((x=x+1))
done

 

[tikual]

Sorry, may has a typo. If the while loop not work,
change as follows:
while (( $x < 12 ));
to
while [[ $x < 12 ]];

cheers