taking password input

[ankursaxena]

Hi! i want to be able to take in a password from the prompt. is there a function which gets the char from the keyboard but doesnt echo it to the screen like most gets do. or if there is a better way or some way that i can input a password and not display anything on the screen, that would be great. thanx a lot in advance.

 

[Jeffray]

try this:

#include <conio.h>
#include <stdio.h>

void main( void )
{

char password[100];
int i =0;
printf (&quot;Input the password:&quot;
char ch;
do {
while( !_kbhit()); // wait for the char;
ch = _getch();
if (ch != 13) password[i++] = ch;
else password = '\0';
} while (ch !=13);

printf( &quot;\n%s\n&quot;,password);
}

 

[ankursaxena]

Hi! thanx a ton, it works perfect, but i am sorry i forgot to mention one small detail on UNIX, this wouldnt compile on unix cuz of conio.h and if there is a different header file that i can include for the kbhit function in unix please let me know thanx a ton for this example.( it might be helpful when i am doing it on windows sometime)

 

[Jeffray]

this one should work in Unix.

#include <stdio.h>
#include <unistd.h>
#include <sys/time.h>
#include <sys/types.h>
#include <sgtty.h>

int u_getchar(void)
{
int ret;
fd_set rfc;
unsigned char buf;

if(read(0, &buf, 1)!=1) ret=0;
else ret=buf;
return ret;
}

int main(void)
{

struct timeval tv;
struct sgttyb ots,ts;
tv.tv_sec = 2;
tv.tv_usec = 0;

gtty(0, &ots);

ts = ots;

// disable the screen echo
ts.sg_flags |= RAW;
ts.sg_flags &=~ ECHO;

stty(0,&ts);

char password[100];
int i =0;
char key = 0;
do{
key = u_getchar();
if(key!=13) password[i++] = key;
else password = '\0';
} while(key!=13);

printf(&quot;\n%s\n&quot;, password);

// reset tty
stty(0,&ots);
}

 

[Guest_imported]

thanx a lot, i havent tried it, but i am sure it must work.