system() does not execute command 1

[flubbard]

I would like my script to make a call to a host stored program. The program is one which I have written can compiled and runs fine from the command line. However, when passed through the system() call, I get nothing back. The relevant portion of code looks like this:

if ($generate)
{
	$command = "myexecutable";
	echo system($command, $return_val) . "<br>";
	echo $return_val; 
}

I have put the executable in many different locations (thinking that I was having a problem with symbolic links or something like that). I have also tried giving it the full path to where it is stored. I have had no luck.

I can, however, set $command = "ls" and get a directory list like I would expect. The file permissions on the executable should be 777 at this point to allow any and all access.

Furthermore, I have not been able to get any useful error feedback to the web browser. I would like to see what error message is being display (i.e. No file exists, permission denied, etc.) I get no output from the file, nor is a file created that should be done by the executable. The return code that I receive ($return_val) is an 11, which is not produced by my program.

Any help would be greatly appreciated.

 

[sleipnir214]

The program is one which I have written can compiled and runs fine from the command line.

Runs fine from the command-line as which user? When run through a web server, the command will run using the permissions of the user as which your web server runs. Did you test the program under that user?


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[flubbard]

That was it, it was a file permission problem. Works now. In the future, do you know of a way to get the stderr redirected so that it outputs in the php script. I was getting a seg fault because apache did not have write access on the drive the output file was to be stored to.