syntax perl vs php

[edpatterson]

No, I am not looking to start a holy war, I am looking for expalinations in converting perl syntax to php.

I tried this code:[tt]
<?php
$var1 = 8;
$var2 = 1;
print "$var1 < $var2 -- ".$var1 < $var2."<br />";
?>[/tt]
and received a blank page. Changing it to:
<?php[tt]
$var1 = 8;
$var2 = 1;
print "$var1 < $var2 -- ";
print $var1 < $var2;
?>[/tt]
returns
8 < 1 --
I was expecting:
8 < 1 -- True (or 1 or any non zero number)

I thought the . was the concatenation operator and I assumed the boolean test would return it's value.

Thanks for any pointers.
Ed

 

[trollacious]

Try putting this:

$var1 < $var2

inside parentheses:

($var1 < $var2)

Lee

 

[Lrnmore]

For some reason the false condition kills the string.
Giving you nothing in your first example.

PHP returns an "" empty string for false and 1 for true so you could do this:

echo "$var1 > $var2 -- ".strlen($var1 > $var);

Good Place to "Learn More">>
W3 Schools

http://www.w3schools.com

 

[edpatterson]

Thanks, I just noticed that my example returned false and not true. I guess I should have my coffee before coding.

Thanks too for the link 'Good Place to "Learn More">>'. A very nice site. I'll have to see if they sell coffee cups. I'll get one to put next to my Tek-Tips cup. A very nice cup by the way.

Ed

 

[Lrnmore]

You're welcome.

Yes, I agree it should always be coffee then code.
And some mornings it should be coffee, coffee then code.

Thanks,
Mark