Syntax for command line parameter into program

[cmarchman]

I have looked through the postings and FAQ and am unable to find the specifics on this question. It may be there and I may be querying correctly.

Anyway, I am trying to figure out how to pass a parameter into a program from the command line. I have seen the following:

perl -w myscript.pl name=bob

Is there a line of the magic ARGV in myscript.pl or is it one of the assumed aspects of Perl?

What I am attempting to do is pass an IP address into a Perl script that will use that IP to query a MySQL db for predetermined fields.

I have used ascript.pl < IP.txt to pull in IP addresses, but that is using a file not an argument.

I am using
while (<>){
$input = "$_";
}

and then variable $input is used in a DBI call into MySQL.

Any assistance is appreciated.

 

[nawlej]

Check out documentation on the Getopt::Long module. It should be able to do what your asking. Of course, you can take in your variable as an @ARGV, split them on the = sign, but Getopt is a pretty cool module to use when doing this sort of thing.

___________________________________
[morse]--... ...--[/morse], Eric.

 

[cmarchman]

nawlej,

Thanks for the pointers. I've looked over Getopt::Long and I'm more interested in the usage of @ARGV. Is there an example of the syntax used to split the @ARGV?

Here's an example of what I'm looking for:

myIPscript.pl 10.2.13.41 (the IP address as the ARGV passed to myIPscript.pl). How do you use split for the @ARGV, I'm still rather new at this.

Thanks,

cmarchman

 

[Rieekan]

Try:

my $variable = shift(@ARGV);  #grabs the first element in @ARGV and stores it as $variable

And the information on shift from O'Reilly's Perl in a Nutshell:

Removes the first value of @array and returns it, shortening the array by one and moving everything down. If there are no elements in the array, the function returns an undefined value.

- Rieekan

 

[cmarchman]

Rieekan,

Works!!! Thanks.

cmarchman