Sum with decimal 2

[Yarka]

Hi, im trying to get, add several numbers such as:

let C=$A+$B

where variables have values as:
A=00,000000011
B=00,003481000

when I execute this, I have this output:

let: C=00,000000011+00,003481000: value too great for base (error token is "00000001"....

I know it interprets as an octal value.
Then, I've put:
let C=10#$A+10#$B

I put 10# before the variables for interpret decimal value.
I have this output:
C=10#00,000000011+10#00,043083000: value too great for base (error token is "00000001"....

How I can make this sum, with bash scripting?

Thanks.

 

[feherke]

Hi

Are you sure your locale setting has comma ( , ) as decimal separator ? And [tt]bash[/tt] does arithmetic operations only with integers.

[blue]master #[/blue] A=00.000000011

[blue]master #[/blue] B=00.003481000

[blue]master #[/blue] echo "$A+$B" | bc
.003481011

Feherke.

http://rootshell.be/~feherke/

 

[Yarka]

Hi.
Yes, my locale setting has comma as decimal separator. These values are extracted of a file. How I can make this sum if the numbers have comma and nonpoint?

Thanks.

 

[Annihilannic]

Unfortunately it seems that bc is not locale sensitive.

You could be tricky like this:

[tt]$ A=00,000000011
$ B=00,003481000
$ echo "$A+$B" | tr , . | bc | tr . ,
,003481011
$[/tt]


Annihilannic.