Sum Filespace script (KORN)

[heprox]

I'm looking to modify this existing script:

#!/bin/ksh
FILESYSTEMS="/ /usr /var /prod /arch_nb"
for FILESYSTEM in $FILESYSTEMS
do
FREESPACE=$(df -Pk ${FILESYSTEM} | awk '$4 ~ /[0-9]+/{print $4}')
echo "${FILESYSTEM} free space: ${FREESPACE}" \
done

...to tell me the amount of free space (in Mb) for each filesystem, and them total it for the whole LPAR. Anyone?

 

[Mike042]

Hi heprox,

I am puzzled by the df -Pk because -P produces output in 512-byte blocks (but only on some versions of UNIX) and -k produces output in kilobytes (1024-byte blocks).

So, if I understand you correctly, how about something like:

#!/bin/ksh
TOTALFREE=0
FILESYSTEMS="/ /usr /var /prod /arch_nb"
for FILESYSTEM in $FILESYSTEMS
do
   FREESPACE=$(df -k ${FILESYSTEM} | awk '$4 ~ /[0-9]+/ {print $4}')
   ((FREESPACE=FREESPACE/1024))
   ((TOTALFREE=TOTALFREE + FREESPACE))
   (echo "${FILESYSTEM} ${FREESPACE}"
   ) | awk '{printf "%-12s free space: %10d \n",$1,$2}'
done
(echo "${TOTALFREE}"
) | awk '{printf "Total amount free space: %10d Mbytes\n",$1)'

Please note that I haven't tested the above code and I am prone to the occasional typo. Also there are bound to be some awk wizards who can do the above far more efficiently.

Anyway, I hope it helps you.

Mike

 

[columb]

for info - from a report program we use

df -Ik | grep -v Filesystem | awk 'BEGIN {printf ("%-20s\t%s\t%s\t%s\n", "File System", "Total Mb", "Free Mb", "Mount Point")}{ printf ("%-20s\t%.2f\t\t%.2f\t% s\n", $1, $2/1024, $4/1024, $6 )}'

Living with a seeker after the truth is infinitely preferable to living with one who thinks they've found it.

 

[Ygor]

On HP-UX df -P specifies a output format of specific columns.

Rather than loop thru each file-system, you could just use df once, then use awk to re-format the output to what you want, e.g....

#!/bin/ksh
FILESYSTEMS="/ /usr /var /prod /arch_nb"
df -Pk ${FILESYSTEMS} | awk '
  BEGIN {fmt = "%-10s free space: %8i MB\n"}
  $4 ~ /^[0-9]+$/ {
       printf fmt, $6, $4 / 1024;
       sum += $4
  }
  END {printf fmt, "Total", sum / 1024}'

The re-formatted output would look like...
[tt]
/usr free space: 214 MB
/var free space: 327 MB
/ free space: 78 MB
Total free space: 639 MB[/tt]

 

[heprox]

Ygor, I like you statement however in AIX 5.2 something is worng with the syntax I get:

/ free space: %8ii MB
/usr free space: %8ii MB
/var free space: %8ii MB
/prod free space: %8ii MB
/arch_nb free space: %8ii MB
Total free space: %8ii MB

Mike, your statement returns:

2%: 0403-053 Expression is not complete; more tokens exp
ected.

 

[RodKnowlton]

heprox,

Change the fmt string like so:

fmt = "%-10s free space: %8d MB\n"

Yes, there's just a single character change. The default awk in AIX doesn't support the "i"(integer) format string specification.



Rod Knowlton
IBM Certified Advanced Technical Expert pSeries and AIX 5L

 

[PHV]

Just to know, will the following awk script works on AIX ?
BEGIN {
cmd="sync;LANG=C df -tk";fmt="%-28s %-23s%9s %9s %7s\n"
printf fmt,"MountDir","FileSystem","Total(Mb)","Free","Used"
trt=sprintf(fmt,"----------","----------","---------","---------","------")
printf trt
fmt="%-28s %-23s%#9.2f %#9.2f %6.2f%%\n"
while((cmd|getline)==1){
if(substr($1,1,1)=="/"){
mountDir=$1
mountDev=substr($2,1,1)=="(" ? substr($2,2) : $2
sub(/[) \t]*:$/,"",mountDev)
nbFree=(substr($3,1,1)==")" ? $4 : $3)/1000
} else if($0~/otal/){
nbTot=($1~/otal/ ? $2 : $1)/1000
if(nbTot){
printf fmt,mountDir,mountDev,nbTot,nbFree,100*(nbTot-nbFree)/nbTot
tTot+=nbTot;tFree+=nbFree;tNb++
}}
}; close(cmd)
exit
}
END {
if(tTot && tNb>1){
printf trt""fmt,"Summary","All",tTot,tFree,100*(tTot-tFree)/tTot
}}