Substitute ADDDATE in Script

[beaster]

I have a file name cmd_cha that has the following statement in it:

@LABEL BEGIN
@SET LOGFILE=("/home/bham_mta/cmd_program/bh1bsc1_cmd_out&quot
@LOG(LOGFILE)
@SET SWITCH="BH1BSC1"
@CONNECT (SWITCH)
imlct:spg=0;
mcsap:file=tlogio,io1=all,sdate=ADD_DATE,stime=0800;
end;
@CLOSE
@DISCONNECT
@SET LOGFILE=("/home/bham_mta/cmd_program/bh1bsc2_cmd_out&quot
@LOG(LOGFILE)
@SET SWITCH="BH1BSC2"
@CONNECT (SWITCH)
imlct:spg=0;
mcsap:file=tlogio,io1=all,sdate=ADD_DATE,stime=0800;
end;
@CLOSE
@DISCONNECT

I want a small script that will scan the file and susbtitute the actual date of the prior day anywhere it finds the words ADD_DATE in the date format like 20020523

I hope this is pretty easy, I am a bit rushed for time.

Thanks as always for the help!

Beaster

 

[olded]

Hi:

Under Solaris 7 ksh:
#!/bin/ksh

date '+%y%m%d' > date.file
nawk ' BEGIN { getline ddate <&quot;date.file&quot; > 0 }
{
gsub(&quot;ADD_DATE&quot;, ddate)
print $0
} ' input > output
rm date.file


Regards,

Ed

 

[beaster]

Can you tell me what date format that will give me? I am looking for it to be 20020523 format....

Regards,
Beaster

 

[olded]

Beaster:

As I posted it, the date doesn't use the century. It's this format:
020522

Not all the unix variants have a POSIX compliant date. Hard-coding the century should work:

date '+20%y%m%d' > date.file

Regards,


Ed

 

[vgersh99]

Would't the following be &quot;clearer&quot;?


ddate=$(date '+%y%m%d')

nawk -v ddate=${ddate} '
{
gsub(&quot;ADD_DATE&quot;, ddate)
print $0
} ' input > output