strip time stamp from file name

[bankshot6164]

What is the syntax to strip a timestamp from the end of a file name to process through a Unix job script. I am a newbe to UNIX and would appreciate anyones help.
Thanks,
Bankshot

 

[PHV]

man expr

Hope This Helps, PH.
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[sbrews]

can you give an example of what the file name looks like?

 

[bankshot6164]

Hi sbrews,
the input file would be similar to the one below:
CECOLL_AGCY_InputtoDEP_RINTJ750_200702070567436
I would like to able to wild card to the time stamp.
This is the code I have that's NOT working!!! File not Found

case $PARAM1 in
"OC1") FILE=CECOLL_AGCY_InputToDEP_RINTJ617*;;

export ITAS_INTRF_FILE1=$ITAS_INTRF/$FILE
export FILENAME=$FILE

files='ls -lt $ITAS_INTRF|grep
$ITAS_INTRF_FILE1|awk '{print $9}

if [-Z $ITAS_INTRF_FILE1]; then
echo "$EXEC: File $ITAS_INTRF_FILE1 does not exist"
exit $FAILURE
fi

 

[sbrews]

This should do what you want:

case $PARAM1 in 
      "OC1") FILE=`echo CECOLL_AGCY_InputtoDEP_RINTJ750*`;;

# ...
#  Assuming there is more case statments and a esac
#  to close/finish the case statement
# ...

export ITAS_INTRF_FILE1=$ITAS_INTRF/$FILE
export FILENAME=$FILE

# I am assuming that the ITAS_INTRF above is defined elsewhere in your script.
# Also assuming the FILENAME will be used elsewhere in the script.

files=`ls -lt $ITAS_INTRF|grep $FILE|awk '{print $9}'`

#I am assuming the "files=..." line and the one right after 
#it should be one line.  Note the ticks [b]'[/b] and the 
#back ticks [b]`[/b].  The line as originally specified 
#would not work - this new version will - not sure what you 
#are doing with this as its not referenced the code fragment
#- other than assigning a value to it.


if [ -z $ITAS_INTRF_FILE1 ]
then
    echo "$EXEC:  File $ITAS_INTRF_FILE1 does not exist"
    exit $FAILURE
fi

#on the [b]if [-Z $INTAS_INTRF_FILE1][/b], the [b]-Z[/b] 
#needs to be lower case: [b]-z[/b] and whitespace is needed 
#after the [ and before the ].