string.replace syntax 1

[peterpann]

What is the syntax to replace several occurances of characters in a string that each start with "/" and end with "#", each occurance to be replaced by "XXX" ? What is the syntax if the occurances end with a newline ? How can I match a short word without getting matches to longer words that start with the same letters ? Thanks.

 

[feherke]

Hi

You did not gave us too many details. If I did not guessed some of the situations, repeat your questions with some sample data.

What is the syntax to replace several occurances of characters in a string that each start with "/" and end with "#", each occurance to be replaced by "XXX" ?

[gray]# eliminates the delimiters[/gray]
'bla'.replace(/\/[^#]*#/g,'XXX')

[gray]# or[/gray]

[gray]# keeps the delimiters[/gray]
'bla'.replace(/\/[^#]*#/g,'/XXX#')

[gray]# or[/gray]

[gray]# keeps the delimiters, more robust, more expansive[/gray]
'bla'.replace(/(\/)[^#]*(#)/g,'$1XXX$2')

What is the syntax if the occurances end with a newline ?

[gray]# eliminates the newlines[/gray]
'bla'.replace(/foo\n/g,'XXX')

[gray]# or[/gray]

[gray]# keeps the newlines[/gray]
'bla'.replace(/foo\n/g,'XXX\n')

[gray]# or[/gray]
[gray]# keeps the newlines, more robust, more expansive[/gray]
'bla'.replace(/foo([\r\n]{1,2})/g,'XXX$1')

How can I match a short word without getting matches to longer words that start with the same letters ?

See the first code.

Feherke.

http://rootshell.be/~feherke/

 

[peterpann]

feherke
Thanks, just what I needed
peterpann